26.
Calculate the [H+
] in the following
(1) PH 7.38
(ii) PH- 1.2
Answers
Answered by
0
Answer:
sorry don't know
Explanation:
really sorry
Answered by
1
Answer:
PH=−log[H
+
]
Hence, [H
+
]=10
−pH
(a) [H
+
]=10
6.83
=1.48×10
−7
M
(b) [H
+
]=10
1.2
=6.31×10
−2
M
(c)[H
+
]=10
7.38
=4.169×10
−8
M
(d) [H
+
]=10
6.4
=3.981×10
−7
please mark as brainlist
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