Question

Calculate most probable speed of oxygen at 27°c
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Answer 1

Answer:

mass of oxygen

M=32gmol−1=0.032kgmole−1

Temperature T=27∘C=(27+273)K=300K

Root mean square speed, vrms=3RTM−−−−−√=3(8.314)(300)(0.032)−−−−−−−−−−−√=183.6ms−1

Average speed, v=8RTπM−−−−−√=8(8.314)(300)(3.14)(0.032)−−−−−−−−−−−√=445.6ms−1

Most probable speed, vmp=2RTM−−−−−√=2(8.314)(300)(0.032)−−−−−−−−−−−√=394.8ms−1

Answer 2

Answer:

Solution :

Given, Molar mass of oxygen

M=32gmol−1=0.032kgmole−1

Temperature T=27∘C=(27+273)K=300K

Root mean square speed, vrms=3RTM−−−−−√=3(8.314)(300)(0.032)−−−−−−−−−−−√=183.6ms−1

Average speed, v=8RTπM−−−−−√=8(8.314)(300)(3.14)(0.032)−−−−−−−−−−−√=445.6ms−1

Most probable speed, vmp=2RTM−−−−−√=2(8.314)(300)(0.032)−−−−−−−−−−−√=394.8ms−1