Math, asked by bibhutijena100, 8 months ago

26. Find the least number which when divided by 12, 15, 18 and 30 leaves the remainder 6,9,12 and 24 respectively

Answers

Answered by PeepingMoon
17

Hope it helps

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Your answer

In this type of questions , we first find LCM of given numbers and then subtract common value to get the answer.

The LCM of 12 , 15,18 and 30=180. We want the answer 6,9,12 and 24. Now the difference is 6 in each case 12-6=6, 15-6=9,18-6=12 and 30-6=24 .

So, we have to subtract 6 from the LCM→180-6=174

So, (180-6=174) will have remainder of 6,9,12,24 when divided by 12,15,18 and 30 respectively.

hope it helps

Answered by GalaxyDragon
4

Answer:

Answer is 174

Step-by-step explanation:

Since , 12 - 6 , 15 - 9 , 18 - 12, 30 - 24 are all equal to six ,

WE HAVE TO SUBTRACT 6  FROM LCM OF 12, 15, 18 AND 30

LCM (12, 15, 18, 30) = 180

Hence , 180 - 6 = 174

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