Physics, asked by madhusudandas694, 6 months ago

26: Power required to propel a vehicle is expressed as
2815263143
RV/3600 (kw)
RVITOOD (kw)
RV/1800(kw)
RV/2000(kw)​

Answers

Answered by mad210203
0

Power for propulsion =\frac{RV}{3600}

SOLUTION:

  • The motion of a vehicle on road is resisted by various factors such as wind resistance and road resistance.
  • A moving vehicle has to overcome these resistances and also lift the weight of vehicle, hence comes power for propulsion.
  • This power is given by \frac{RV}{3600} ,where R is total resistance and V is speed of vehicle in kilometer per hour.
  • The unit of this power is kilowatt.
  • A moving vehicle must overcome these resistances and produce this amount of power to propel forward in any direction.

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