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The area of a parallelogram is p cm² and its height is q cm. A second parallelogram
has equal area but its base is r сm more than that of the first. Obtain an expression in
terms of p, q and r for the height h of the second parallelogram.
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Answer:
Let the base of the first triangle be 'b' cm.
b×q=p²____(1)
Also, base of 2nd triangle =(b+r)
(b+r)h= p²
(p²/q+r)=p²
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