Question

26. The distance between two protons is 1.0 x 10 m. If they are made free, what will be the kinetic
energy of each when they are away at a very large distance from each other? If one proton is kept
fixed and only other is freed then what will be its kinetic energy ?
Hint: In the first case the potential energy of the protons-system will be equally divided as kinetic
energies of the free protons; in the second case the total potential energy will appear as the kinetic
energy of the freed proton.
Ans. 1.15 x 10-10 J, 2.30 x 10 J.
11. .
10
12​

Answer 1

Answer:

Explanation:

Kinetic energy of each proton is given by:

total kinetic energy = total initial potential energy

i.e u= 1/(4pi epsilon) × (q1q2)/r^2

Substituting the value given

u= {9× (10^9) × (1.6× 10^(-19)) ^2 } ÷ 1 × 10^(-10)

= 23.04× 10^(-19) J

Therefore, kinetic energy of each proton ={23.04 × 10^ (-19)}÷ 2

= 11.52 × 10^(-19) J

Hope, so it will help you !