Math, asked by rhidhunam, 3 months ago

26. The population of a place increased to 54,000 in 2003 at a rate of 5% per annum (i) find
the population in 2001. (ii) what would be its population in 2005?​

Answers

Answered by Anonymous
18

Step-by-step explanation:

Thus, the population in 2001 is 48980 approximately. Now, as a population in 2003 = 54000 . Then, after a 5% increment, the population in 2004 =1.05×54000=56700. Similarly, after a 5% increment, the population in 2005 =1.05×56700=59535 .

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