Question

26. The sum of all natural numbers from 100 to 300 which are exactly divisible by 4 and 5 is
(b) 2,000
(c) 2,220
(d) none of these
(a) 2,200​

Answer 1

(d) none of thess

Step-by-step explanation:

sum of number divisible by 4

=100+104+108+,,,+300

total=51

Sn=n/2[2a+(n-1d)

51/2(200+50×4)

51/2(400)

51×200

10200

sum of number divisible by 5

100+105+110+115+,,,+300

total number = 41

Sn=n/2 [2a+(n-1d)

=41/2 (200+40×5)

=41/2 (400)

=41×200

=8200

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Answer 2

Answer:

Sorry I am in 8th class and I can't..