26. The sum of all natural numbers from 100 to 300 which are exactly divisible by 4 and 5 is
(b) 2,000
(c) 2,220
(d) none of these
(a) 2,200
Answers
Answered by
1
(d) none of thess
Step-by-step explanation:
sum of number divisible by 4
=100+104+108+,,,+300
total=51
Sn=n/2[2a+(n-1d)
51/2(200+50×4)
51/2(400)
51×200
10200
sum of number divisible by 5
100+105+110+115+,,,+300
total number = 41
Sn=n/2 [2a+(n-1d)
=41/2 (200+40×5)
=41/2 (400)
=41×200
=8200
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Answered by
2
Answer:
Sorry I am in 8th class and I can't..
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