Question

26. What is the digit at the tens place of the sum of the four-digit even numbers
formed by using the digits 7, 2, 9, 0 once only?​

Answer 1

My attempt to solve this problem is:

First digit cannot be zero, so the number of choices only 6(1,2,3,4,5,6)

The last digit can be pick from 0,2,4,6, so the number of choices only 4

Second digit can be only pick from the rest, so the number of choices only 5

Third digit can be only pick from the rest, so the number of choices only 4

The total number of choices is 6⋅4⋅5⋅4=480

mark it as brainlist