26400(1+15/100) rays to 2
26400(1+3/20)rays to 2
26400(23/20)
how??
** what is the value of i here
**how will we get 23/20
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Answer:
.Given that,
AB=1m=100cm,
l=40cm
The balancing condition for meter bridge is
R2
R1
=
100−l
l
R1=R2(
100−l
l
)
R1=R2(
100−40
40
)
R1=R2(
60
40
)=
6
4
R2.......(1)
When R2 is shunted by a resistance of 10 , l = 50 cm hence,
R1−10=R2(
100−50
50
)
R1−10=R2
6
4
R2−10=R2 ........from(1)
2R2=10
R2=5Ω
Using this in (1), we get
R1=(
6
4
)5=
3
10
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