2645 - By which smallest number the given number should be divided, so that the result becomes a perfect square? Find the square root of the result obtained.
Answers
Answered by
0
It should be divided by 5
2645/5
=529
=✓23
Answered by
4
Solution :
Resolving 2645 into product of
prime , we get
5 | 2645
________
23| 529
________
******23
2645 = 5 × ( 23 × 23 )
We see that 23 exist in pair.
while 5 is alone .
So , we should divide the given
number by 5 to get a perfect square.
Therefore ,
the perfect square so obtained is
2645 ÷ 5 = 529 = 23²
The square root of 529
= √529
= √( 23 × 23 )
= 23
•••••
Resolving 2645 into product of
prime , we get
5 | 2645
________
23| 529
________
******23
2645 = 5 × ( 23 × 23 )
We see that 23 exist in pair.
while 5 is alone .
So , we should divide the given
number by 5 to get a perfect square.
Therefore ,
the perfect square so obtained is
2645 ÷ 5 = 529 = 23²
The square root of 529
= √529
= √( 23 × 23 )
= 23
•••••
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