Question

26cc of CO2 are passed over red hot coke . The volume of CO evovled

Answer 1

CO2 + C -> 2CO

22.4L 2*22.4L

1 mole of CO2 gives 2 moles of CO

One mole of CO2 =22.4 L = 22400 cc

22400cc CO2 gives CO = 2* 22400 cc

1 cc CO2 gives CO = (2 * 22400)/22400

26cc CO2 gives CO = (2*22400* 26)/22400 = 52cc CO

Volume of CO produced by heating 26 cc of CO2 with red hot coke is 52 cc .

Answer 2

Answer : The volume of CO evolved are, 0.052 L

Explanation : Given,

Volume of $CO_2$ = $26cm^3=0.026L$

conversion : $(1cm^3=10^{-3}L)$

The balanced chemical reaction will be,

$CO_2+C\rightarrow 2CO$

From the balanced chemical reaction, we conclude that the mole ratio of $CO_2$ and $CO are 1 : 2</p><p><strong>As we know that,</strong></p><p>1 mole of gas contains 22.4 L volume of gas.</p><p>As, 22.4 L volume of [tex]CO_2$ gas gives $2\times 22.4L$ volume of CO gas

As, 0.026 L volume of $CO_2$ gas gives $\frac{22.4}{0.026}\times 2\times 22.4L=0.052L$ volume of CO gas

Therefore, the volume of CO evolved are, 0.052 L