Math, asked by shreyashraj72134, 23 hours ago

26xy(xy+5y-4x-20) ÷ 104(xy-4x)​

Answers

Answered by lubnaqaisar03
1

\LARGE \text{\tt{\underline{Solution:}}}

\begin{array}{l}{\tt{26 x y \cdot(x y+5 y-4 x-20) \div 104(x y-4 x) \\\\{\tt{26 x y \cdot(x y+5 y-4 x-20)\left(\frac{1}{104}\right)(x y-4 x) \\\\{\tt{26 x y \cdot \frac{x y+5 y-4 x-20}{104}(x y-4 x) \\\\\end{array}

\begin{array}{l}{\tt{26 x y \cdot \frac{y\left(\frac{x y}{y}+\frac{5 y}{y}\right)+2^{2}\left(-\frac{2^{2} \cdot x}{2^{2}}-\frac{2^{2} \cdot 5}{2^{2}}\right)}{104}(x y-4 x)\\\\{\tt{26 x y \cdot \frac{y(x+5)+2^{2}(-x-5)}{104}(x y-4 x)\\\\{\tt{26 x y \cdot \frac{(x+5)\left(\frac{y(x+5)}{x+5}+\frac{2^{2}(-x-5)}{x+5}\right)}{104}(x y-4 x)\\\\\end{array}

\begin{array}{l}{\tt{26 x y \cdot \frac{(x+5)\left(y-\left(2^{2}\right)\right)}{104}(x y-4 x) \\\\{\tt{26 x y \cdot \frac{(x+5)(y-4)}{104}(x y-4 x) \\\\{\tt{\frac{26 x y(x+5)(y-4)(x y-4 x)}{104} \\\\{\tt{\frac{2 \cdot 13 x y(x+5)(y-4)(x y-4 x)}{2 \cdot 2 \cdot 2 \cdot 13} \\\\{\tt{\frac{x y(x+5)(y-4)(x y-4 x)}{2 \cdot 2} \\\\{\tt{\frac{x y(x+5)(y-4)(x y-4 x)}{4}\\\end{array}

\LARGE \text{\tt{\underline{Answer:}}}

{\boxed{\tt{\frac{x y(x+5)(y-4)(x y-4 x)}{4}}}

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