Question

(27/125)^1/3×[(3/2)^-2+(2/5)^3]-4(3/7)^0

Answer 1

(27/125)^1/3×[(3/2)^-2+(2/5)^3]-4(3/7)^0 = -3.69

Step-by-step explanation:

(27/125)^1/3×[(3/2)^-2+(2/5)^3]-4(3/7)^0

= ( 3³/5³)^1/3  * [ (2/3)²  + (2/5)³]  - 4 * 1

= ((3/5)³)^1/3 * [ 4/9 + 8/125]  - 4

= (3/5)  * [572 / (9 * 125)]  - 4

=  572/1875 - 4

=( 572 - 7500 ) /1875

= -6928/1875

= -3.69

or Question can be

(27/125)^1/3×[(3/2)^-2 ÷ (2/5)^3]-4(3/7)^0

= ( 3³/5³)^1/3  * [ (2/3)²  * (5/2)³]  - 4 * 1

= ((3/5)³)^1/3 * [ (4/9 )* (125/8)]  - 4

= (3/5)  * [125/18)]  - 4

= 25/6 - 4

=( 25 - 24 ) /6

= 1/6

Learn more:

(27/125)^1/3×[(3/2)^-2÷(2/5)^3]-4(3/7)^0

https://brainly.in/question/15026801