Question

27(a+b)^3+8(2a-b)^3​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

We know,

a3+b3+c3−3abc=(a+b+c)(a2+b2+c2−ab−bc−ca)

If,                a+b+c=0 then,

a3+b3+c3−3abc=0

=>a3+b3+c3=3abc

Now,

27(a−b)3+(2a−b)3+(4b−5a)3

=(3a−3b)3+(2a−b)3+(4b−5a)3

Here,

a=3a−3b

b=2a−b

c=4b−5a

Now,

a+b+c=3a−3b+2a−b+4b−5a

                =0

Thus,

(3a−3b)3+(2a−b)3+

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