Question

27. A ball is dropped from a certain height. If it takes
0.2 s to cross the last 6.2 m before hitting the
ground, find the height from which it was dropped.
(Take g = 10 m s-2)​

Answer 1

Answer:

48.05m

Explanation:

here is your answer

3rd equation of motion is v²-u²=2as

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Answer 2

Answer:

last part of journey

s=ut+(1\2)GT square

here s=6.3 m

u =?

t= 0.2 seconds

g= 10m s-2

putting these value we get

u=30m\s

for the upper portion

v square = u square +2gh

here u =0

and v= 30m\s

putting values we get h=45m

so the total length is

45+6.2=51.2