27. A human male is heterozygous for autosomal genes 'A' and 'B'. He is also
hemizygous for haemophilic gene 'h'. What percentage of sperms will carry 'abh'
genotype?
A) 25%
B) 50%
C) 75%
D) 0%
Answers
Explanation:
The following genotype is formed in the human male where the autosomal genes are "A" and "B" respectively for Hemizygous genes it's given as a autosomal haemophilic gene that is, "h".
This sets a genotypic character of \bf{Aa \: Bb \: X^h \: Y}AaBbX
h
Y , since, as per the original question of a sufferer from Haemophilia will contain the Haemophilic gene it'll be a se.x characterised trait linked to the genes that are attached to the X-Chtomosomes.
Therefore, the total number and types of gametes going to be formed are:
\bf{ 2 \times 2 \times 2 = 8 \: gametes}2×2×2=8gametes
Cross linking them simultaneously will give us the following combinations:
\bf{AB \: X^h, \: ABY, \: aB \: X^h, \: aBY, \: AbY, \: ab \: X^h \: and \: abY}ABX
h
,ABY,aBX
h
,aBY,AbY,abX
h
andabY
\bf{ab X^h}abX
h
is the gene found to be the proportional gene pit of those 8 gametes.
So, total \begin{gathered}\bf{\frac{1}{8}} \\\end{gathered}
8
1
of his sp.erms are going to be in a combination of "abh".
HOPE THIS DETAILED ANSWER HELPS YOU AND CLEARS THE DOUBTS FOR GENOTYPIC INHERITANCE!!!!!!!!
Answer:
the answer is 12.5 per cent but it is not in option
