Question

In the given figure, point P is equidistant from two intersecting lines, intersects on point A. prove that ∆ABP and ∆ACP are congruent and length of AC is 8 cm ​

Answer 1

Here we go ⬇️

in traingle abp and triangle acp

ap =ap ( common )

no= mp( length are equal )

angle abp = angle amp ( each 90 )

by rhs congruency

∆ Abp congruent ∆ acp

follow me ✌️

Answer 2

Answer:

AP= AP (COMMON)

ANGLE B= ANGLE C ( EACH 90)

CP= BP. ( because point p is equidistant hence this lines are equal)

Hence ABP congruent ACP

by SAS congruence rule