Math, asked by gayatriroutray74196, 1 month ago

27) A man bought two articles for Rs. 120 each. He sold
one of the articles at a loss of 10% and the second at
10% gain. For how much money did he sell both the
articles ?

Answers

Answered by JamButter
14

Answer:

price of both articles=Rs.120

10% of 120=120*10/100=Rs.12

Selling price of the first article=120-12

=Rs.108

Selling price of the second article=120+12

=Rs.132

So,the price of first article is Rs.108 and the price of second artice is Rs.132 and the man experienced 0% gain or loss

HOPE IT HELPS YOU

PLZ MARK ME AS THE BRAINLIEST

Answered by 8adarshtanwal
2

answer is 1 for this equation

Similar questions