27 drops of same size are charged at 220V each. They coalesce to form a bigger drop. Calculate the potential of the bigger drop?
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The radius of the bigger drop will be
3
4
πR
3
=27×
3
4
πr
3
R=3r
the potential of the small drop
=
r
KQ
=v
The potential of the big drop
Q=nq=27q
V
′
=
R
KQ
=
3r
K×27q
= 9v
9×220
= 1980 V
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