Math, asked by salfara9384, 1 year ago

Solve each of the following equation;
3\10x+12=4\10x=28

Answers

Answered by kuldeep9415193112
3

Answer:

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Step-by-step explanation:

Solution for 3/10x+12=4/10x-28 equation:

3/10x+12=4/10x-28

We move all terms to the left:

3/10x+12-(4/10x-28)=0

Domain of the equation: 10x!=0

x!=0/10

x!=0

x∈R

Domain of the equation: 10x-28)!=0

x∈R

We get rid of parentheses

3/10x-4/10x+28+12=0

We multiply all the terms by the denominator

28*10x+12*10x+3-4=0

We add all the numbers together, and all the variables

28*10x+12*10x-1=0

Wy multiply elements

280x+120x-1=0

We add all the numbers together, and all the variables

400x-1=0

We move all terms containing x to the left, all other terms to the right

400x=1

x=1/400

x=1/400

Answered by chavisharma282
0

Answer:

please

Step-by-step explanation:

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