Question

27. Find the thrust required to exert a pressure of 3000 Pa on an area of contact of 3m. * (1 Point) 1000N 0.001N 9000N 9000 Pa​

Answer 1

• Pressure=3000Pa
• Area=3m^2

Thrust means force

$\boxed{\sf P=\dfrac{F}{A}}$

• P denotes to pressure
• F denotes to thrust force
• A denotes to area

$\\ \sf\longmapsto F=PA$

$\\ \sf\longmapsto Force=3000(3)$

$\\ \sf\longmapsto Force=9000N$

Answer 2

Question :-

• Find the Thrust required to exert a pressure of 3000 Pascal on an Area of of contact of 3 meter .

• 1000 N
• 0.001 N
• 9000 N
• 9000 Pascal

Answer :-

• The required Thrust is 9000 N .

$\rule {180pt} {2pt}$

Given :-

• Pressure = 3000 Pascal
• Area = 3 meter

To Find :-

• Thrust = ?

Solution :-

As per the provided information in the given question, we have been given that the Pressure is 3000 Pascal . Area is given 3 meter . And, we have to find the Thrust .

For calculating the Thrust , we will use Formula :-

• Force = Pressure × Area

Therefore , by substituting the given values in the above Formula :-

⇒ Force = Pressure × Area

⇒ Force = 3000 × 3

⇒ Force = 9000

Hence :-

• Thrust = 9000 N .

$\underline {\rule {180pt} {4pt}}$