Question

27. Find the zeroes of the polynomial x2-3 and verify the relationship between the
zeroes and the coefficients of the polynomial.​

Answer 1

Answer:

Here's the answer

Step-by-step explanation:

x^2-3

=> (x-√3)(x+√3)

=> x = √3 ,-√3

let aplha = √3 and beta = -√3

alpha +beta = -b/a

= 0/1

=0

aplha × beta = c/a

= -3/1

= -3