Question

.
27. Find the zeroes of the polynomial x2-3 and verify the relationship between the
zeroes and the coefficients of the polynomial.​

Answer 1

Answer:

$-\sqrt{3} , + \sqrt{3}$

Step-by-step explanation:

$p(x) =x^{2} - 3$ = 0

⇒$(x)^{2} - (\sqrt{3} )^{2} = 0$

⇒$(x-\sqrt{3} ) (x + \sqrt{3} ) = 0$

⇒$x -\sqrt{3} = 0$ or $(x+ \sqrt{3} ) =0$

⇒x = $\sqrt{3}$ or x= $- \sqrt{3}$

verification

sum of the roots = -b/a

LHS: $\sqrt{3\\}$ - $\sqrt{3}$ =0

RHS: -0/1 = 0

LHS=RHS

Product of the roots = c/a

LHS: $\sqrt{3\\}$ × $- \sqrt{3}$ = -3

RHS: -3/1 = -3

LHS = RHS

HENCE VERIFIED.