27. If 5 tane = 4, what will be the value of 5sine - 3cose where is an acute angle? Øsine + 2cose
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1
Explanation:
Divide the numerator and denomenator by cosθ
cosθ
5sinθ+2cosθ
cosθ
5sinθ−3cosθ
⇒
cosθ
5sinθ
+
cosθ
2cosθ
3cosθ
5sinθ
−
cosθ
3cosθ
⇒
5tanθ+2
5tanθ−3
Substituting the value of 5tanθ, we get
⇒
4+2
4−3
=
answer=1/6
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