Question

27 or,.......,.... I'll make you As the brainliest ans

Answer 1

Answer:

Step-by-step explanation:

Question 27 uses value of tan 60° and tan 45°.

In the figure, tan 60° = AD/BD and tan 45° = AD/CD.

All we need is BD + CD.

And here AD = 150 m.

BD = AD/tan 60° ⇒ BD = $150/\sqrt{3} =50\sqrt{3}$ m

CD = AD/tan 45° ⇒ CD = $150/1=150$ m

∴ BD = $50(3+\sqrt{3} )$ m

The speed is $25(3+\sqrt{3} )$ m/min.

Answer 2

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