27 solid sphere each of radius 2cm are melted to form a ne solid sphere. what will be the surfac area of new sphere
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Volume of 27 solid spheres each of radius 2 cm
= 27× 4/3 × πr³ = 27 × 4/3 × π(2)³ = 27 × 32π/3 = 288π
Volume of new solid sphere = volume of 27 solid spheres
4/3 × πr³ = 288π
r³ = 288π×3/4π = 216
r = ∛216 = 6 cm
Surface area of new sphere of radius 6 cm
= 4πr² = 4π(6)² = 452.39 cm² Ans.
= 27× 4/3 × πr³ = 27 × 4/3 × π(2)³ = 27 × 32π/3 = 288π
Volume of new solid sphere = volume of 27 solid spheres
4/3 × πr³ = 288π
r³ = 288π×3/4π = 216
r = ∛216 = 6 cm
Surface area of new sphere of radius 6 cm
= 4πr² = 4π(6)² = 452.39 cm² Ans.
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Volume of 27 solid spheres each of radius 2 cm = >27× 4/3 × πr³ = >27 × 4/3 × π(2)³ = >27 × 32π/3 = >288π
Volume of new solid sphere = volume of 27 solid spheres
4× πr³/3 =>288π
r³ = 288π×3/4π = >216
r = ∛216 = >6 cm
Surface area of new sphere of radius 6 cm = 4πr² = 4π(6)² = 452.39 cm²
Volume of new solid sphere = volume of 27 solid spheres
4× πr³/3 =>288π
r³ = 288π×3/4π = >216
r = ∛216 = >6 cm
Surface area of new sphere of radius 6 cm = 4πr² = 4π(6)² = 452.39 cm²
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