Question

27. The equivalent weight of FeS2 in the following
reaction is Fes2+ 02 → Fe+3+ So2
Mol. wt
(1) Mol. wt
(2)
7
Mol. wt
Mol. wt
(3)
(4)
11
9​

Answer 1

Answer:

FeS+O

2

⟶Fe

+3

+SO

2

Here, as S

2

has oxidation state 2−

Fe has oxidation state 2+

After oxidation Fe has oxidation state 3+

∴ No. of e

−

transferred=3−2=Ie

−

We know,

Equivalent weight=

nfactor

Molecularweight

Here n factor is no. of e

−

transferred as this is a redox reactor.

∴ Equivalent weight=

1

Mol.wt

Explanation:

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