Question

27. The height and radius of the base of a cone are increased by 100%. How
many times is the volume of the new cone of the volume of former original
(Assistant Grade Exam.)
cone 2​

Answer 1

So. volume becomes eight times when radius and height are doubled.

ANSWER

Let the radius and height of the cone be R and H then

V1=31×π×(R)2×(H)

When radius and heigh are increased by 100% then

V2=31×π×(2R)2×(2H)

V2=8×31×π×(R)2×(H)

Hence,

 V2=8×(V1)

So. volume becomes eight times when radius and height are doubled.

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