Question

27. The value of (-6) 101 is positive. T/F​

Answer 1

Answer:

F(t)} = LX! e-st F(t)dt = 101 te-ddt + 12(2 - t)e- Itdt ... (b) With F(t) = t3e-t , we have 1(8) = 6/(s + 1 )4 and as F(t) -t 0 as t -t 00 and 81(8) also tends to the limit 0 as 8 -t 0 the final value theorem

Answer 2

false

(-6)101

= -606

is not positive