Question

27 : What is the value of side AC if AB =
7 cm and BC = 5 cm? | यदि AB = 7 सेमी
और BC = 5 सेमी है तो भुजा AC का मान क्या​

Answer 1

Answer:

using Pythagoras theorem h^2 = √ l^2 + b^2

AC^2 = √AB^2 + BC^2

= √ 7^2 cm+ 5^2cm

= √49 cm + 25 cm

= √ 74 cm

AC = 8 . 60

hope it helps

Answer 2

Answer:

9 cm is the required value of side AC of a triangle ABC.

Step-by-step explanation:

Explanation:

Given in the question that, AB = 7cm and BC = 5cm.

• The Pythagorean theorem, sometimes known as Pythagoras' theorem, is a fundamental relationship between a right triangle's three sides in Euclidean geometry.

• The Pythagorean Theorem states that the square on the hypotenuse of a right triangle is equal to the sum of the squares on the triangle's legs.

Step 1:

Let ABC is a 'right angle triangle'.

Now, by 'Pythagoras theorem'

$AC^2 = AB ^2 + BC^2$

⇒AC = $\sqrt{AB^2 + BC^2}$

⇒AC = $\sqrt{5^2 + 7^2}$                      [AB = 7cm and BC = 5cm given]

⇒AC = $\sqrt{25 + 49}$ = $\sqrt{74}$ = 8.602 cm

So, AC = 9 cm.

Final answer:

Hence, the value of side AC = 9cm.

#SPJ2