(27)^x / 3^y + 4 = 1 and
8^4-x/3 - 16y= 0
find x and y
answer should come
x=4 and y=2
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Step-by-step explanation:
(27)^x / 3^y + 4 = 1 and
8^4-x/3 - 16y= 0
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