27 x cube y cube minus 8 Z cube
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Solution :
Given 27x³y³ - 8z³
= 3³x³y³ - 2³z³
= ( 3xy )³ - ( 2z )³
= (3xy-2z)[(3xy)²-3xy•2z+(2z)²]
= (3xy-2z)(9x²y²-6xy+4z²)
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Answer:
answer is in the attachment
Step-by-step explanation:
hope it helps you ......
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in this we just have to take the cube roots .and they we will get the a and b term then we will apply formula a²+b²+2ab .
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