Question

27 x cube + y cube + Z cube minus 9 x y z factorise​

Answer 1

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Answer 2

$\huge\mathfrak{Answer}$

We can write:

27x³ + y³ + z³ - 9xyz

= (3x)³ + y³ + z³ - 3 (3x) yz

= (3x + y + z) [(3x)² + y² + z² - (3x) y - yz - (3x) z]

[Using Identity

a³ + b³ + c³ - 3abc =

( a + b + c ) ( a² + b² + c² - ab - bc - ca ).

Here a = 3x, b = y, c = z]

= (3x + y + z) (9x² + y² + z² - 3xy - yz - 3xy)