Question

27 x3 + y² + z3 - 9xyz​

Answer 1

27x

3

+y

3

+z

3

−9xyz

=(3x)

3

+y

3

+z

3

−9xyz

=(3x)

3

+y

3

+z

3

−3×3x×y×z

using identity

a

3

+b

3

+c

3

−3abc=(a+b+c)(a

2

+b

2

+c

2

−ab−bc−ca)

Putting a=3x,b=y,c=z

=(3x+y+z)(9x

2

+y

2

+z

2

−3xy−yz−3zx).

Answer 2

Answer:

firstly the Ques is 27x³+y³+z³-9xyz

Step-by-step explanation:

now (3x)³+(y)³+(z)³-3(3x)(y)(z)

so now,

the factorisation will be (3x+y+z)(9x²+y²+z²-3xy-yz-3zx)