27 x3 + y² + z3 - 9xyz
Answers
Answered by
0
27x
3
+y
3
+z
3
−9xyz
=(3x)
3
+y
3
+z
3
−9xyz
=(3x)
3
+y
3
+z
3
−3×3x×y×z
using identity
a
3
+b
3
+c
3
−3abc=(a+b+c)(a
2
+b
2
+c
2
−ab−bc−ca)
Putting a=3x,b=y,c=z
=(3x+y+z)(9x
2
+y
2
+z
2
−3xy−yz−3zx).
Answered by
1
Answer:
firstly the Ques is 27x³+y³+z³-9xyz
Step-by-step explanation:
now (3x)³+(y)³+(z)³-3(3x)(y)(z)
so now,
the factorisation will be (3x+y+z)(9x²+y²+z²-3xy-yz-3zx)
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