?2704 x ?2209=? what is the process of solving these questions?
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In terms of simplifying it to solve it more easily, you can use the properties of FOIL.
(a+b)*(c+d) = a*c+b*c+a*d+b*d
what you have is 2704 * 2209
To make it similar to the properties of FOIL, you can split the numbers up.
2704 = 3000 - 296
2209 = 2000 + 209
2704 * 2209 = (3000 - 296)*(2000 + 209) = 3000 * 2000 - 296 * 2000 + 209 * 3000 - 296 * 209
You can further simplify this by repeating the steps
-296*2000 = (-300 + 4) * 2000 = -300 * 2000 + 4 * 2000
209*3000 = (200 + 9) * 3000 = 200 * 3000 + 9 * 3000
-296 * 209 = (-300 +4)*(200 + 9)
I'm sure you can finish from here. It's essentially taking one method and repeating it multiple times to make the numbers easier to multiply.
(a+b)*(c+d) = a*c+b*c+a*d+b*d
what you have is 2704 * 2209
To make it similar to the properties of FOIL, you can split the numbers up.
2704 = 3000 - 296
2209 = 2000 + 209
2704 * 2209 = (3000 - 296)*(2000 + 209) = 3000 * 2000 - 296 * 2000 + 209 * 3000 - 296 * 209
You can further simplify this by repeating the steps
-296*2000 = (-300 + 4) * 2000 = -300 * 2000 + 4 * 2000
209*3000 = (200 + 9) * 3000 = 200 * 3000 + 9 * 3000
-296 * 209 = (-300 +4)*(200 + 9)
I'm sure you can finish from here. It's essentially taking one method and repeating it multiple times to make the numbers easier to multiply.
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