Math, asked by noorghy7861, 8 months ago

273070 and 434330 hcf by Euclid division
algorithm

Answers

Answered by Abdulrazak182
1

434330÷273070=273070×1+161260

273070÷161260=161260×1+111810

161260÷111810=111810×1+49450

111810÷49450=49450×2+12910

49450÷12910=12910×3+10720

12910÷10720=10720×1+2190

10720÷2190=2190×4+1960

2190÷1960=1960×1+230

1960÷230=230×80+120

230÷120=120×1+110

120÷110=110×1+10

110÷10=10×11+0

=11

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