Question

27g Al reacts with 98g H2SO4. Calculate the volume of H2 evolved and percentage of aluminum reacted with H2SO4. Al+H2SO4 ------> H2(SO4)3+H2​

Answer 1

Answer:

Explanation:

equivalent method

equivalent of al = 3

equivalent of h2so4 = 2

less equivalent acts limiting reagent and products also have equivalent equal to limiting

equivalent of h2 released = 2

moles*2 = 2

moles = 1

volume = 22.4 lts

equivalent reacted with h2so4 = 2

moles*3 = 2

moles = 0.67

mass = 18 gm

percentage aluminium reacted = 2/3 *100 = 67 percent

mole method

2al+3h2so4 = al2(so4)3 +3 h2

mole/sc for al = 0.5

mole/sc for h2so4  = 0.34

moles of h2 formed = 0.34*3 = 1

volume evolved = 22.4 lts

aluminium left = moles - moles*limiting ratio

=1-0.34

=0.66

aluminium moles reacted = 0.34

mass reacted  = 9 gm