27g of Al will react completely with how many grams of oxygen?
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Answer:
2Al+ 3/2 O2 ⟶Al2O3
Moles of Al= 27/27 =1 mol
2 mole Al gives 3/2 mole O2
1 mole Al gives 3/4 mole O2
Mass of oxygen = 3/4×32=24 gram
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