27p^3 - 64q^3 By identify
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27p³-64q³
(3p)³-(4q)³
(3p-4q)[(3p)²+3p×4q+(4q)²]
(3p-4q)(9p²+12pq+16q²)
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Use this identity
↓↓↓↓↓↓↓
a³-b³
(a-b)(a²+ab+b²)
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★Hope it helps uh!!!
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Question : -
27p^3 - 64q^3 By identity
Solution : -
Applying this identity a³-b³ = (a-b)(a²+ab+b²)
27p³ - 64q³
(3p)³ - (4q)³
(3p-4q) [(3p)² + 3p×4q + (4q)²]
(3p-4q) [9p²+12pq+16q²]
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