Math, asked by vb94165, 9 months ago

27p^3 - 64q^3 By identify​

Answers

Answered by Anonymous
5

\huge\bold\red{Solution}

27p³-64q³

(3p)³-(4q)³

(3p-4q)[(3p)²+3p×4q+(4q)²]

(3p-4q)(9p²+12pq+16q²)

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Use this identity

-b³

(a-b)(+ab+)

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Hope it helps uh!!!

Answered by MяƖиνιѕιвʟє
2

Question : -

27p^3 - 64q^3 By identity

Solution : -

Applying this identity -b³ = (a-b)(+ab+)

27p³ - 64q³

(3p)³ - (4q)³

(3p-4q) [(3p)² + 3p×4q + (4q)²]

(3p-4q) [9p²+12pq+16q²]

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