Math, asked by SRjohn, 10 months ago

(27x^3 +3x^2-2x +8) ÷ (3x- 2)

Answers

Answered by Anonymous

7

$(27x^{3} + 3x ^{2} - 2x + 8) \div (3x - 2) \\ = \\$

Answered by ItzSmartyYashi

0

$\huge{\underline{\underline{\mathfrak{Answer}}}}$

27x

3

+3x

2

−2x+8)÷(3x−2)

$\huge{\underline{\underline{\mathfrak{Thank you}}}}$

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