Question

27x^3 y^3 - 45x^4 y^2

factorise

Answer 1

$27x^3 y^3 - 45x^4 y^2 \\= 9x^{3} y^{2} \times 3y - 9x^{3}y^{2} \times 5x\\= 9x^{3}y^{2} (3y-5x)$

Therefore.,

$\red{ Factors \:of \: 27x^3 y^3 - 45x^4 y^2}\\\green { = 9x^{3}y^{2} (3y-5x) }$

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Answer 2

Answer:

=9x3y2×3y−9x3y2×5x=9x3y2(3y−5x)

Therefore.,

\begin{gathered}\red{ Factors \:of \: 27x^3 y^3 - 45x^4 y^2}\\\green { = 9x^{3}y^{2} (3y-5x) }\end{gathered}Factorsof27x3y3−45x4y2=9x3y2(3y−5x)