Question

27x² - 10x + 1 = 0 where i = √-1​

Answer 1

Answer:

$27x^{2} -10x +1=0$

Step-by-step explanation:

by formula method $\frac{-b+-\sqrt{}b^{2-4ac} }{2a}$

x = - (-10) +-  suqare root( (-10)^2 -4* 27 * 1)  /2 *27

x=  10 +- square root ( 100 -108) /54

x = 10 +-  square root (-8) /54

x = 10 +- 2$\sqrt{2 i}$ / 54

Answer 2

Answer:

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