(27x³-8) by (3x-2) divide the expression
Sona1916:
9x^2+6x+4
Answers
Answered by
4
Remainder is 0 and quotient is 9x²+6x+4
ryt
Pls thank me and start following me
Answered by
13
Hi ,
( 27x³ - 8 ) / ( 3x - 2 )
= [ (3x)³ - 2³ ] / ( 3x - 2 )
= [ (3x - 2 ) (9x² + 6x + 4 )] / ( 3x - 2 )
= ( 9x² + 6x + 4 )
I hope this helps you.
:)
( 27x³ - 8 ) / ( 3x - 2 )
= [ (3x)³ - 2³ ] / ( 3x - 2 )
= [ (3x - 2 ) (9x² + 6x + 4 )] / ( 3x - 2 )
= ( 9x² + 6x + 4 )
I hope this helps you.
:)
ryt
Similar questions