27x3+y3+z3-9xyz factorize
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Identity :- a3 + b3 + c3 - 3abc = (a+b+c) (a sq. + b sq. + c sq. -ab -bc -ac)
(3x)^3 + (y)^3 + (z)^3 - 3(3x) (y) (z)
= ( 3x+y+z ) ( 9x^2 + y^2 + z^2 - 3x.y - y.z - z.3x )
= ( 3x+y+z ) ( 9x^2 + y^2 + z^2 - 3xy -yz - 3zx ) ans..
(3x)^3 + (y)^3 + (z)^3 - 3(3x) (y) (z)
= ( 3x+y+z ) ( 9x^2 + y^2 + z^2 - 3x.y - y.z - z.3x )
= ( 3x+y+z ) ( 9x^2 + y^2 + z^2 - 3xy -yz - 3zx ) ans..
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