Question

27y^(3)+123x^(3) factorise

Answer 1

Answer:

use Identity x³+y³ = (x+y)(x²-xy+y²)

Answer 2

$= 27y {}^{3} + 123x {}^{3} \\ \\ = (3y) {}^{3} + ( \sqrt[3]{123} x) {}^{3} \\ \\ (3y + \sqrt[3]{123} )((3y) {}^{2} + (\sqrt[3]{123} ) {}^{2} - 3y. \sqrt[3]{123} \\ \\ (3y + \sqrt[3]{123})(9y {}^{2} + ( \sqrt[3]{123} ) - 3y. \sqrt[3]{123}$

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formula uses

$\star\pink{(a^3+b^3)=(a+b)(a^2+b^2-ab)}$

I hope it helps you