28-[19-{11-(7-6+?)}]
hemantvats17:
equal to me kya hai??
Answers
Answered by
0
let ? be x
28-[19-{11-(7-6+x)}]=9
28 = 9+[19-{11-(7-6+x)}]
28-9 = 19-{11-(7-6+x)}
19 = 19-{11-(7-6+x)}
19+{11-(7-6+x)}=19
11-(7-6+x)=19-19
11-(7-6+x) =0
11=7-6+x
11=1+x
x=10
28-[19-{11-(7-6+x)}]=9
28 = 9+[19-{11-(7-6+x)}]
28-9 = 19-{11-(7-6+x)}
19 = 19-{11-(7-6+x)}
19+{11-(7-6+x)}=19
11-(7-6+x)=19-19
11-(7-6+x) =0
11=7-6+x
11=1+x
x=10
plz mark me as brainliest
Answered by
2
28 - [ 19 - { 11 - ( 7 - 6 + ? )}]
by trial method
let' ?' be "x "
substituting "x "in ?
28 - [ 19 - { 11 - ( 7 - 6 + x )}] = 0
28 - [ 19 - { 11 - (1 + x )}] = 0
28 - [ 19 - { - 11 - 11 x }] = 0
28 - [ 19 + 11 + 11 x ] = 0
28 - 30 + 11 x = 0
- 2 + 11 x = 0
11 x = 2
× = 2/11
by trial method
let' ?' be "x "
substituting "x "in ?
28 - [ 19 - { 11 - ( 7 - 6 + x )}] = 0
28 - [ 19 - { 11 - (1 + x )}] = 0
28 - [ 19 - { - 11 - 11 x }] = 0
28 - [ 19 + 11 + 11 x ] = 0
28 - 30 + 11 x = 0
- 2 + 11 x = 0
11 x = 2
× = 2/11
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