28. A body is moving on a circular path such that its
angular velocity a changes as a = (t2-2t) rad/sec.
If radius of circular path is 2m then tangential
acceleration at t = 2 sec is :-
(1) 8 m/sec2
(2) 4 m/sec
(3) 2m/sec2
(4) None
Answers
Answered by
3
Answer:
option 1 ................
Answered by
11
Given: Angular velocity ν = (t²-2t)
radius of circular path = 2m
time = 2sec
To find: tangential acceleration
Solution: Tangential acceleration is represented by = αr
angular acceleration α = dν/dt
=d(t²-2t)/dt
= 2t-2
At t = 2 sec, putting its value in equation , 2×2 - 2 = 2
Tangential acceleration = αr
= 2 × 2 = 4ms⁻²
Therefore, tangential acceleration is 4 ms⁻².
The correct option of the following question is (2).
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