Question

28. A g of a metal displaces mL of H2 at NTP. Equivalent
mass E, of metal is.
4
(a) E =
x Ен
mass of Hy displaced
4x1.008 22400
(b) E
volume of H, displaced x 2
A x1.008
(c) E =
volume of H2 displaced x 0.0000897
(d) all of the above​

Answer 1

Equivalent weight is the mass which displaces 11.2L of H2 In Volume

So, equivalent mass of element = 2 X 11200/V g.