Question

28.A refrigerator box contains 2 milk
chocolates and 4 dark chocolates.
Two chocolates are drawn at random.
Find the probability distribution of
the number of milk chocolates. What
is the most likely outcome? [1 marks]​

Answer 1

Answer:

2/4

1l2

answer is 1/2

dark chocolate is the most likely outcomes

Answer 2

Given, box contains 2 milk and 4 dark chocolates and two are drawn at random ( without replacement).

X= 0

P(X)= $\frac{4}{6} X \frac{3}{5} = \frac{12}{30}$                  ( Only dark chocolates)

Out of 6 chocolates ( in total) 4 are dark, so the first chocolate would be 4/6 and the second dark would be 3/5 as one is already taken.

X=1

p(X) = $\frac{2}{6} X\frac{4}{5} + \frac{2}{5} X\frac{4}{6}$   = $\frac{16}{30}$         ( One milk and one dark chocolate)

Here one is milk and other is dark .

X= 2

P(X) = $\frac{2}{6} X\frac{1}{5} = \frac{2}{30}$                   ( Both are milk chocolates)

Out of 6 chocolates ( in total) 2 are milk, so the first chocolate would be 2/6 and the second dark would be 1/5 as one is already taken.

From observing the above results, it can be seen the most likely outcome is that one chocolate would be milk while the other would be dark.

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